合并JsonObj
首页 > 杂记    作者:StanWind   2018年1月13日 19:24 星期六   热度:551°   百度已收录  
时间:2018-1-13 19:24   热度:551° 
public static void mergeJSONTo(JSONObject main, JSONObject b) {
        JSONObject rtn = main;
        for (String key : b.keySet()) {
            if (rtn.containsKey(key)) {
                Object o = rtn.get(key);
                Object bO = b.get(key);
                if (o instanceof List && bO instanceof List) {
                    List rA = (List) o;
                    List bA = (List) bO;
                    rA.addAll(bA);
                } else if (o instanceof Number && bO instanceof Number) {
                    if (o instanceof Double) {
                        Double na = (Double) o;
                        Double nb = (Double) bO;
                        rtn.put(key, na + nb);
                    } else if (o instanceof Float) {
                        Float na = (Float) o;
                        Float nb = (Float) bO;
                        rtn.put(key, na + nb);
                    } else if (o instanceof Long) {
                        Long na = (Long) o;
                        Long nb = (Long) bO;
                        rtn.put(key, na + nb);
                    } else if (o instanceof Integer) {
                        Integer na = (Integer) o;
                        Integer nb = (Integer) bO;
                        rtn.put(key, na + nb);
                    } else if (o instanceof Short) {
                        Short na = (Short) o;
                        Short nb = (Short) bO;
                        rtn.put(key, na + nb);
                    } else if (o instanceof Byte) {
                        Byte na = (Byte) o;
                        Byte nb = (Byte) bO;
                        rtn.put(key, na + nb);
                    } else {
                        System.err.println("[Add] Can't merge JSONObJ for Error Type for A : " + o.getClass().toString()
                                + " B: " + bO.getClass().toString());
                    }
                } else if (o instanceof JSONObject && bO instanceof JSONObject) {
                    rtn.put(key, mergeJSON(rtn.getJSONObject(key), b.getJSONObject(key)));
                    //保留 A的
                } else {
                    System.err.println("[Arrays] Can't merge JSONObJ for Error Type for A : " + o.getClass().toString()
                            + " B: " + bO.getClass().toString());
                }
            } else {
                rtn.put(key, b.get(key));
            }
        }

    }

    /**
     * 合并json 出现数组自动合并
     */
    public static JSONObject mergeJSON(JSONObject a, JSONObject b) {
        JSONObject rtn = fromObject(a);

        for (String key : b.keySet()) {
            if (rtn.containsKey(key)) {
                Object o = rtn.get(key);
                Object bO = b.get(key);
                if (o instanceof List && bO instanceof List) {
                    List rA = (List) o;
                    List bA = (List) bO;
                    rA.addAll(bA);
                } else if (o instanceof Number && bO instanceof Number) {
                    if (o instanceof Double) {
                        Double na = (Double) o;
                        Double nb = (Double) bO;
                        rtn.put(key, na + nb);
                    } else if (o instanceof Float) {
                        Float na = (Float) o;
                        Float nb = (Float) bO;
                        rtn.put(key, na + nb);
                    } else if (o instanceof Long) {
                        Long na = (Long) o;
                        Long nb = (Long) bO;
                        rtn.put(key, na + nb);
                    } else if (o instanceof Integer) {
                        Integer na = (Integer) o;
                        Integer nb = (Integer) bO;
                        rtn.put(key, na + nb);
                    } else if (o instanceof Short) {
                        Short na = (Short) o;
                        Short nb = (Short) bO;
                        rtn.put(key, na + nb);
                    } else if (o instanceof Byte) {
                        Byte na = (Byte) o;
                        Byte nb = (Byte) bO;
                        rtn.put(key, na + nb);
                    } else {
                        System.err.println("[Add] Can't merge JSONObJ for Error Type for A : " + o.getClass().toString()
                                + " B: " + bO.getClass().toString());
                    }
                } else if (o instanceof JSONObject && bO instanceof JSONObject) {
                    rtn.put(key, mergeJSON(rtn.getJSONObject(key), b.getJSONObject(key)));
                    //保留 A的
                } else {
                    System.err.println("[Arrays] Can't merge JSONObJ for Error Type for A : " + o.getClass().toString()
                            + " B: " + bO.getClass().toString());
                }
            } else {
                rtn.put(key, b.get(key));
            }
        }

        return rtn;
    }

    //数组合并测试
    public static void main(String[] args) {
        /*JSONObject o = new JSONObject();
        JSONArray a = new JSONArray();
        JSONArray aa = new JSONArray();
        for (int i = 0; i < 5; i++) {
            a.add("aaaaa" + i);
            aa.add("a1a1a1" + i);
        }
        o.put("aa", a);
        o.put("a1", aa);


        JSONObject t = new JSONObject();
        JSONArray bb = new JSONArray();
        JSONArray b = new JSONArray();
        for (int i = 0; i < 5; i++) {
            b.add("bbbbb" + i);
            bb.add("b1b1b1" + i);
        }
        t.put("aa", b);
        t.put("a1", bb);*/
        JSONObject a = new JSONObject();
        JSONObject b = new JSONObject();
        JSONObject aa = new JSONObject();
        JSONObject bb = new JSONObject();
        a.put("t", aa);
        b.put("t", bb);
        for (int i = 1; i < 4; i++) {
            aa.put("a" + i, 1);
            bb.put("a" + i, i);
        }


        System.out.println(a.toJSONString());
        System.out.println(b.toJSONString());
        System.out.println("merge->" + mergeJSON(a, b).toJSONString());
        System.out.println(a.toJSONString());
        System.out.println(b.toJSONString());
        mergeJSONTo(a, b);
        System.out.println("mergeTo->" + a.toJSONString());
        System.out.println(a.toJSONString());
        System.out.println(b.toJSONString());
    }
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本文作者:StanWind      文章标题: 合并JsonObj
本文地址:https://www.stanwind.com/post/68
版权声明:若无注明,本文皆为“Make it Better”原创,转载请保留文章出处。

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